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2x^2+29x-8.3=0
a = 2; b = 29; c = -8.3;
Δ = b2-4ac
Δ = 292-4·2·(-8.3)
Δ = 907.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{907.4}}{2*2}=\frac{-29-\sqrt{907.4}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{907.4}}{2*2}=\frac{-29+\sqrt{907.4}}{4} $
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